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Old 17-04-2003   #12
Andre Wiethoff
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Yes... All C1/C2 correction circuits usually work deterministic, from which follows that the result on the same (wrong) C1/C2 information will always be the same.
But these CDs are like already scratched CDs (with many read errors). So there is no buffer for some wrong symbols on a sector anymore. Any new scratch/hair /whatever will cause a real read error with a much higher probability!
So, do you like to buy a new CD that is already scratched?? That is what you have done!

cu, Andre
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