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Well, actually, if 10641 is the total numbers of errors and if 1930 were at the same place, and if the drive properly interpolates, then a file should have 1930+(10641-1930)/2=6085 errors in average.
Thus the proportion of consistent errors is 1930/6085*100 = 32% not 18 !
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Pio2001
Last edited by Pio2001 on 30-09-2003 at 00:40
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